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x^2+1.25x=0.375
We move all terms to the left:
x^2+1.25x-(0.375)=0
We add all the numbers together, and all the variables
x^2+1.25x-0.375=0
a = 1; b = 1.25; c = -0.375;
Δ = b2-4ac
Δ = 1.252-4·1·(-0.375)
Δ = 3.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.25)-\sqrt{3.0625}}{2*1}=\frac{-1.25-\sqrt{3.0625}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.25)+\sqrt{3.0625}}{2*1}=\frac{-1.25+\sqrt{3.0625}}{2} $
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